A LEVEL MATHEMATICS

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The Mailbox

Posted by White Group Mathematics on January 12, 2018 at 12:20 AM |

Hello Mr Koh,

I recently encountered a problem in my holiday revision package which asked us to discover the equations of the tangents fo the curve ** x^2- axy +y^2 =a ** which are parallel to the y-axis. I managed to compute an expression via implicit differentiation for the gradient function, ie dy/dx = (ay-2x)/ (2y-ax) which I am not sure if it is correct; I also do not really know how to proceed from here. Could you please advise?

Student X

Hi,

The expression for dy/dx obtained is absolutely accurate. With regards to finding the necessary tangent equations, you shall have to set dx/dy=0 , thereafter inject the result arising from this back into the original curve equation. Kindly find my set of workings in full below, hope it helps. Peace.

Best Regards,

Mr Koh

Categories: Math Queries

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