|Posted by White Group Mathematics on March 10, 2015 at 2:20 AM|
The question asks,
A body moving in a straight line with constant acceleration takes 3 sec and further 5 sec to cover two successive distances of 1m. Find acceleration.(Hint: use distances of 1m and 2m from the start of motion)
I cannot seem to figure out how to solve this. Could you please show the calculations to get the same answer presented in the book, which is -1/30 m/s^2 ?
Let us use s=ut+1/2 * at^2
When the first metre is covered, substituting s=1 and t=3 gives
3u+ 9a/2 = 1 -----------------(1)
When the first two metres are covered, substituting s=2 and t= 3+5=8 gives
8u+ 32a = 2 ====> 4u+16a =1 -------(2)
Solve these two equations simultaneously, you should be able to retrieve the answer for the acceleration shortly.
Categories: Math Queries